(x+3)^2+12=156

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Solution for (x+3)^2+12=156 equation: 



(x+3)^2+12=156

We move all terms to the left:

(x+3)^2+12-(156)=0

We add all the numbers together, and all the variables

(x+3)^2-144=0

We move all terms containing x to the left, all other terms to the right

(x+3)^2=144

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